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5=x^2/3600-60x
We move all terms to the left:
5-(x^2/3600-60x)=0
Domain of the equation: 3600-60x)!=0We get rid of parentheses
We move all terms containing x to the left, all other terms to the right
-60x)!=-3600
x!=-3600/1
x!=-3600
x∈R
-x^2/3600+60x+5=0
We multiply all the terms by the denominator
-x^2+60x*3600+5*3600=0
We add all the numbers together, and all the variables
-1x^2+60x*3600+18000=0
Wy multiply elements
-1x^2+216000x+18000=0
a = -1; b = 216000; c = +18000;
Δ = b2-4ac
Δ = 2160002-4·(-1)·18000
Δ = 46656072000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{46656072000}=\sqrt{14400*3240005}=\sqrt{14400}*\sqrt{3240005}=120\sqrt{3240005}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(216000)-120\sqrt{3240005}}{2*-1}=\frac{-216000-120\sqrt{3240005}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(216000)+120\sqrt{3240005}}{2*-1}=\frac{-216000+120\sqrt{3240005}}{-2} $
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